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40542451130131 is a prime number
BaseRepresentation
bin10010011011111100001100…
…11001011101111100010011
312022112211011010102120110221
421031332012121131330103
520303221414442131011
6222120540034333511
711353044506423026
oct1115760631357423
9168484133376427
1040542451130131
1111a10a587a5995
124669494a2a297
1319811a1546342
14a0239d6391bd
154a490760c971
hex24df8665df13

40542451130131 has 2 divisors, whose sum is σ = 40542451130132. Its totient is φ = 40542451130130.

The previous prime is 40542451130123. The next prime is 40542451130141. The reversal of 40542451130131 is 13103115424504.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 40542451130131 - 23 = 40542451130123 is a prime.

It is a super-2 number, since 2×405424511301312 (a number of 28 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (40542451130141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20271225565065 + 20271225565066.

It is an arithmetic number, because the mean of its divisors is an integer number (20271225565066).

Almost surely, 240542451130131 is an apocalyptic number.

40542451130131 is a deficient number, since it is larger than the sum of its proper divisors (1).

40542451130131 is an equidigital number, since it uses as much as digits as its factorization.

40542451130131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 28800, while the sum is 34.

Adding to 40542451130131 its reverse (13103115424504), we get a palindrome (53645566554635).

The spelling of 40542451130131 in words is "forty trillion, five hundred forty-two billion, four hundred fifty-one million, one hundred thirty thousand, one hundred thirty-one".