Base | Representation |
---|---|
bin | 10010011100000101111100… |
… | …00100100100100011001011 |
3 | 12022120022122112201222102002 |
4 | 21032002332010210203023 |
5 | 20303313122104043223 |
6 | 222123202550301215 |
7 | 11353321212334115 |
oct | 1116027604444313 |
9 | 168508575658362 |
10 | 40547680143563 |
11 | 11a131a140209a |
12 | 466a4b405780b |
13 | 198182597a128 |
14 | a02737cb23b5 |
15 | 4a4b116eee28 |
hex | 24e0be1248cb |
40547680143563 has 2 divisors, whose sum is σ = 40547680143564. Its totient is φ = 40547680143562.
The previous prime is 40547680143521. The next prime is 40547680143569. The reversal of 40547680143563 is 36534108674504.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 40547680143563 - 218 = 40547679881419 is a prime.
It is a super-2 number, since 2×405476801435632 (a number of 28 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 40547680143499 and 40547680143508.
It is not a weakly prime, because it can be changed into another prime (40547680143569) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20273840071781 + 20273840071782.
It is an arithmetic number, because the mean of its divisors is an integer number (20273840071782).
Almost surely, 240547680143563 is an apocalyptic number.
40547680143563 is a deficient number, since it is larger than the sum of its proper divisors (1).
40547680143563 is an equidigital number, since it uses as much as digits as its factorization.
40547680143563 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 29030400, while the sum is 56.
The spelling of 40547680143563 in words is "forty trillion, five hundred forty-seven billion, six hundred eighty million, one hundred forty-three thousand, five hundred sixty-three".
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