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40551125440541 is a prime number
BaseRepresentation
bin10010011100001100010110…
…11011010101100000011101
312022120122112122200012100212
421032012023123111200131
520303342201103044131
6222124532503102205
711353502456020532
oct1116061333254035
9168518478605325
1040551125440541
1111a146aa166771
12466b0b5a41965
131981c546a27b1
14a029836b0d89
154a4c63e03a2b
hex24e18b6d581d

40551125440541 has 2 divisors, whose sum is σ = 40551125440542. Its totient is φ = 40551125440540.

The previous prime is 40551125440537. The next prime is 40551125440547. The reversal of 40551125440541 is 14504452115504.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 32415202099225 + 8135923341316 = 5693435^2 + 2852354^2 .

It is a cyclic number.

It is not a de Polignac number, because 40551125440541 - 22 = 40551125440537 is a prime.

It is a super-2 number, since 2×405511254405412 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (40551125440547) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20275562720270 + 20275562720271.

It is an arithmetic number, because the mean of its divisors is an integer number (20275562720271).

Almost surely, 240551125440541 is an apocalyptic number.

It is an amenable number.

40551125440541 is a deficient number, since it is larger than the sum of its proper divisors (1).

40551125440541 is an equidigital number, since it uses as much as digits as its factorization.

40551125440541 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 320000, while the sum is 41.

The spelling of 40551125440541 in words is "forty trillion, five hundred fifty-one billion, one hundred twenty-five million, four hundred forty thousand, five hundred forty-one".