Base | Representation |
---|---|
bin | 111011000000101101000… |
… | …000111010000100001111 |
3 | 112100200012011101201212201 |
4 | 323000231000322010033 |
5 | 1012420024302334413 |
6 | 12342533554342331 |
7 | 565656513104536 |
oct | 73005500720417 |
9 | 15320164351781 |
10 | 4055204339983 |
11 | 1323891149345 |
12 | 555b1388a9a7 |
13 | 235533b40874 |
14 | 1003b6d2331d |
15 | 707426bb9dd |
hex | 3b02d03a10f |
4055204339983 has 2 divisors, whose sum is σ = 4055204339984. Its totient is φ = 4055204339982.
The previous prime is 4055204339951. The next prime is 4055204339999. The reversal of 4055204339983 is 3899334025504.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4055204339983 - 25 = 4055204339951 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4055204334983) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2027602169991 + 2027602169992.
It is an arithmetic number, because the mean of its divisors is an integer number (2027602169992).
Almost surely, 24055204339983 is an apocalyptic number.
4055204339983 is a deficient number, since it is larger than the sum of its proper divisors (1).
4055204339983 is an equidigital number, since it uses as much as digits as its factorization.
4055204339983 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13996800, while the sum is 55.
The spelling of 4055204339983 in words is "four trillion, fifty-five billion, two hundred four million, three hundred thirty-nine thousand, nine hundred eighty-three".
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