40613381 has 2 divisors, whose sum is σ = 40613382. Its totient is φ = 40613380.

The previous prime is 40613341. The next prime is 40613387. The reversal of 40613381 is 18331604.

40613381 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 40576900 + 36481 = 6370^2 + 191^2 .

It is a cyclic number.

It is not a de Polignac number, because 40613381 - 2¹⁰ = 40612357 is a prime.

It is a super-2 number, since 2×40613381² = 3298893432502322, which contains 22 as substring.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 40613381.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (40613387) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20306690 + 20306691.

It is an arithmetic number, because the mean of its divisors is an integer number (20306691).

Almost surely, 2^40613381 is an apocalyptic number.

It is an amenable number.

40613381 is a deficient number, since it is larger than the sum of its proper divisors (1).

40613381 is an equidigital number, since it uses as much as digits as its factorization.

40613381 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1728, while the sum is 26.

The square root of 40613381 is about 6372.8628574605. The cubic root of 40613381 is about 343.7344404638.

Adding to 40613381 its reverse (18331604), we get a palindrome (58944985).

The spelling of 40613381 in words is "forty million, six hundred thirteen thousand, three hundred eighty-one".