Base | Representation |
---|---|
bin | 10010011110001110110011… |
… | …10110000011011111001011 |
3 | 12022211100022112002002102002 |
4 | 21033013121312003133023 |
5 | 20311014114044403303 |
6 | 222221034210301215 |
7 | 11361532140413321 |
oct | 1117073166033713 |
9 | 168740275062362 |
10 | 40621160544203 |
11 | 11a41379154728 |
12 | 46807a058780b |
13 | 198873618b135 |
14 | a06108c23d11 |
15 | 4a69b264a788 |
hex | 24f1d9d837cb |
40621160544203 has 2 divisors, whose sum is σ = 40621160544204. Its totient is φ = 40621160544202.
The previous prime is 40621160544161. The next prime is 40621160544257. The reversal of 40621160544203 is 30244506112604.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 40621160544203 - 216 = 40621160478667 is a prime.
It is a super-3 number, since 3×406211605442033 (a number of 42 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (40621160544803) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20310580272101 + 20310580272102.
It is an arithmetic number, because the mean of its divisors is an integer number (20310580272102).
Almost surely, 240621160544203 is an apocalyptic number.
40621160544203 is a deficient number, since it is larger than the sum of its proper divisors (1).
40621160544203 is an equidigital number, since it uses as much as digits as its factorization.
40621160544203 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 138240, while the sum is 38.
Adding to 40621160544203 its reverse (30244506112604), we get a palindrome (70865666656807).
The spelling of 40621160544203 in words is "forty trillion, six hundred twenty-one billion, one hundred sixty million, five hundred forty-four thousand, two hundred three".
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