Base | Representation |
---|---|
bin | 100101110111000110… |
… | …001000010100111011 |
3 | 10212221011102021120212 |
4 | 211313012020110323 |
5 | 1131224104120324 |
6 | 30401534341335 |
7 | 2636262052463 |
oct | 456706102473 |
9 | 125834367525 |
10 | 40652801339 |
11 | 162714a0387 |
12 | 7a6665a84b |
13 | 3aab3a7647 |
14 | 1d7917aba3 |
15 | 10cde8470e |
hex | 97718853b |
40652801339 has 2 divisors, whose sum is σ = 40652801340. Its totient is φ = 40652801338.
The previous prime is 40652801291. The next prime is 40652801341. The reversal of 40652801339 is 93310825604.
40652801339 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-40652801339 is a prime.
Together with 40652801341, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 40652801296 and 40652801305.
It is not a weakly prime, because it can be changed into another prime (40652801389) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20326400669 + 20326400670.
It is an arithmetic number, because the mean of its divisors is an integer number (20326400670).
Almost surely, 240652801339 is an apocalyptic number.
40652801339 is a deficient number, since it is larger than the sum of its proper divisors (1).
40652801339 is an equidigital number, since it uses as much as digits as its factorization.
40652801339 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 155520, while the sum is 41.
The spelling of 40652801339 in words is "forty billion, six hundred fifty-two million, eight hundred one thousand, three hundred thirty-nine".
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