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4072057921213 is a prime number
BaseRepresentation
bin111011010000011001100…
…100001101111010111101
3112102021200201101100222221
4323100121210031322331
51013204033311434323
612354402205205341
7600124251143062
oct73203144157275
915367621340887
104072057921213
11132aa4a5a1377
12559237b60851
13236cbb6ba139
141011353aac69
1570dcc0c055d
hex3b41990debd

4072057921213 has 2 divisors, whose sum is σ = 4072057921214. Its totient is φ = 4072057921212.

The previous prime is 4072057921187. The next prime is 4072057921307. The reversal of 4072057921213 is 3121297502704.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3486592686564 + 585465234649 = 1867242^2 + 765157^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4072057921213 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 4072057921213.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4072057922213) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2036028960606 + 2036028960607.

It is an arithmetic number, because the mean of its divisors is an integer number (2036028960607).

Almost surely, 24072057921213 is an apocalyptic number.

It is an amenable number.

4072057921213 is a deficient number, since it is larger than the sum of its proper divisors (1).

4072057921213 is an equidigital number, since it uses as much as digits as its factorization.

4072057921213 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 211680, while the sum is 43.

The spelling of 4072057921213 in words is "four trillion, seventy-two billion, fifty-seven million, nine hundred twenty-one thousand, two hundred thirteen".