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407401555213 is a prime number
BaseRepresentation
bin1011110110110110000…
…01100110010100001101
31102221120111220022222101
411323123001212110031
523133324244231323
6511054021115101
741301535040122
oct5733301462415
91387514808871
10407401555213
11147861614384
1266b59b58a91
132c557bab703
1415a0b1aa749
15a8e65d1dad
hex5edb06650d

407401555213 has 2 divisors, whose sum is σ = 407401555214. Its totient is φ = 407401555212.

The previous prime is 407401555111. The next prime is 407401555219. The reversal of 407401555213 is 312555104704.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 404137375524 + 3264179689 = 635718^2 + 57133^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-407401555213 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (407401555219) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 203700777606 + 203700777607.

It is an arithmetic number, because the mean of its divisors is an integer number (203700777607).

Almost surely, 2407401555213 is an apocalyptic number.

It is an amenable number.

407401555213 is a deficient number, since it is larger than the sum of its proper divisors (1).

407401555213 is an equidigital number, since it uses as much as digits as its factorization.

407401555213 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 84000, while the sum is 37.

Adding to 407401555213 its reverse (312555104704), we get a palindrome (719956659917).

The spelling of 407401555213 in words is "four hundred seven billion, four hundred one million, five hundred fifty-five thousand, two hundred thirteen".