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40805251033 is a prime number
BaseRepresentation
bin100110000000001011…
…101011011111011001
310220022210021112020211
4212000023223133121
51132032121013113
630425022051121
72643122624311
oct460013533731
9126283245224
1040805251033
111633a556068
127aa9719aa1
133b03b53571
141d91502441
1510dc549b3d
hex9802eb7d9

40805251033 has 2 divisors, whose sum is σ = 40805251034. Its totient is φ = 40805251032.

The previous prime is 40805251031. The next prime is 40805251037. The reversal of 40805251033 is 33015250804.

40805251033 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 29421854784 + 11383396249 = 171528^2 + 106693^2 .

It is a cyclic number.

It is not a de Polignac number, because 40805251033 - 21 = 40805251031 is a prime.

It is a super-2 number, since 2×408052510332 (a number of 22 digits) contains 22 as substring.

Together with 40805251031, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 40805250986 and 40805251004.

It is not a weakly prime, because it can be changed into another prime (40805251031) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20402625516 + 20402625517.

It is an arithmetic number, because the mean of its divisors is an integer number (20402625517).

Almost surely, 240805251033 is an apocalyptic number.

It is an amenable number.

40805251033 is a deficient number, since it is larger than the sum of its proper divisors (1).

40805251033 is an equidigital number, since it uses as much as digits as its factorization.

40805251033 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 14400, while the sum is 31.

The spelling of 40805251033 in words is "forty billion, eight hundred five million, two hundred fifty-one thousand, thirty-three".