Base | Representation |
---|---|
bin | 101110011001000100100010… |
… | …1101110000110101110100111 |
3 | 1222111211201201000211022212112 |
4 | 1130302021011232012232213 |
5 | 411441223143200211142 |
6 | 4003514534352111235 |
7 | 151644540124665416 |
oct | 13462110556065647 |
9 | 1874751630738775 |
10 | 408066012507047 |
11 | 10902790788a484 |
12 | 39925b15b3551b |
13 | 146905c942686b |
14 | 72aa7010c347d |
15 | 3229b005a0382 |
hex | 1732245b86ba7 |
408066012507047 has 2 divisors, whose sum is σ = 408066012507048. Its totient is φ = 408066012507046.
The previous prime is 408066012507017. The next prime is 408066012507103. The reversal of 408066012507047 is 740705210660804.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 408066012507047 - 210 = 408066012506023 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 408066012506986 and 408066012507004.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (408066012507017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 204033006253523 + 204033006253524.
It is an arithmetic number, because the mean of its divisors is an integer number (204033006253524).
Almost surely, 2408066012507047 is an apocalyptic number.
408066012507047 is a deficient number, since it is larger than the sum of its proper divisors (1).
408066012507047 is an equidigital number, since it uses as much as digits as its factorization.
408066012507047 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2257920, while the sum is 50.
The spelling of 408066012507047 in words is "four hundred eight trillion, sixty-six billion, twelve million, five hundred seven thousand, forty-seven".
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