Base | Representation |
---|---|
bin | 111011011101001000000… |
… | …001010011100000010011 |
3 | 112110120222000010122202112 |
4 | 323131020001103200103 |
5 | 1013420024340400313 |
6 | 12404542130135535 |
7 | 601120001454566 |
oct | 73351001234023 |
9 | 15416860118675 |
10 | 4085722200083 |
11 | 1335821738327 |
12 | 55ba101215ab |
13 | 2383885a2154 |
14 | 101a700524dd |
15 | 7142b9da8a8 |
hex | 3b748053813 |
4085722200083 has 2 divisors, whose sum is σ = 4085722200084. Its totient is φ = 4085722200082.
The previous prime is 4085722199987. The next prime is 4085722200149. The reversal of 4085722200083 is 3800022275804.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4085722200083 - 232 = 4081427232787 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 4085722200083.
It is not a weakly prime, because it can be changed into another prime (4085722200883) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2042861100041 + 2042861100042.
It is an arithmetic number, because the mean of its divisors is an integer number (2042861100042).
Almost surely, 24085722200083 is an apocalyptic number.
4085722200083 is a deficient number, since it is larger than the sum of its proper divisors (1).
4085722200083 is an equidigital number, since it uses as much as digits as its factorization.
4085722200083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 215040, while the sum is 41.
Adding to 4085722200083 its reverse (3800022275804), we get a palindrome (7885744475887).
The spelling of 4085722200083 in words is "four trillion, eighty-five billion, seven hundred twenty-two million, two hundred thousand, eighty-three".
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