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409052445120953 is a prime number
BaseRepresentation
bin101110100000001111111000…
…1101011111001100110111001
31222122100000212012211010111022
41131000133301223321212321
5412103403401422332303
64005552033222312225
7152106030626604104
oct13500376153714671
91878300765733438
10409052445120953
11109378193328397
1239a65130288675
131473263190379a
14730235b6a773b
1532455d5b8a438
hex17407f1af99b9

409052445120953 has 2 divisors, whose sum is σ = 409052445120954. Its totient is φ = 409052445120952.

The previous prime is 409052445120937. The next prime is 409052445120989. The reversal of 409052445120953 is 359021544250904.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 341901844585744 + 67150600535209 = 18490588^2 + 8194547^2 .

It is a cyclic number.

It is not a de Polignac number, because 409052445120953 - 24 = 409052445120937 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 409052445120895 and 409052445120904.

It is not a weakly prime, because it can be changed into another prime (409052445123953) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 204526222560476 + 204526222560477.

It is an arithmetic number, because the mean of its divisors is an integer number (204526222560477).

Almost surely, 2409052445120953 is an apocalyptic number.

It is an amenable number.

409052445120953 is a deficient number, since it is larger than the sum of its proper divisors (1).

409052445120953 is an equidigital number, since it uses as much as digits as its factorization.

409052445120953 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7776000, while the sum is 53.

The spelling of 409052445120953 in words is "four hundred nine trillion, fifty-two billion, four hundred forty-five million, one hundred twenty thousand, nine hundred fifty-three".