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40932571313 is a prime number
BaseRepresentation
bin100110000111110001…
…010111100010110001
310220122122212001211202
4212013301113202301
51132312214240223
630445411020545
72646230054414
oct460761274261
9126578761752
1040932571313
11163a5407737
127b2429a755
133b243413ca
141da43a5b7b
1510e87e9428
hex987c578b1

40932571313 has 2 divisors, whose sum is σ = 40932571314. Its totient is φ = 40932571312.

The previous prime is 40932571301. The next prime is 40932571327. The reversal of 40932571313 is 31317523904.

40932571313 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 28799108209 + 12133463104 = 169703^2 + 110152^2 .

It is a cyclic number.

It is not a de Polignac number, because 40932571313 - 26 = 40932571249 is a prime.

It is not a weakly prime, because it can be changed into another prime (40932541313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20466285656 + 20466285657.

It is an arithmetic number, because the mean of its divisors is an integer number (20466285657).

Almost surely, 240932571313 is an apocalyptic number.

It is an amenable number.

40932571313 is a deficient number, since it is larger than the sum of its proper divisors (1).

40932571313 is an equidigital number, since it uses as much as digits as its factorization.

40932571313 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 68040, while the sum is 38.

The spelling of 40932571313 in words is "forty billion, nine hundred thirty-two million, five hundred seventy-one thousand, three hundred thirteen".