Base | Representation |
---|---|
bin | 111011101010011100001… |
… | …111110110001000111001 |
3 | 112111221212110100022100202 |
4 | 323222130033312020321 |
5 | 1014133320132344433 |
6 | 12415305010011545 |
7 | 602134215452534 |
oct | 73523417661071 |
9 | 15457773308322 |
10 | 4100020199993 |
11 | 1340899574283 |
12 | 562740576bb5 |
13 | 23982685b623 |
14 | 102628d3ba1b |
15 | 719b6d84ee8 |
hex | 3ba9c3f6239 |
4100020199993 has 2 divisors, whose sum is σ = 4100020199994. Its totient is φ = 4100020199992.
The previous prime is 4100020199971. The next prime is 4100020200053. The reversal of 4100020199993 is 3999910200014.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4092982164544 + 7038035449 = 2023112^2 + 83893^2 .
It is a cyclic number.
It is not a de Polignac number, because 4100020199993 - 212 = 4100020195897 is a prime.
It is not a weakly prime, because it can be changed into another prime (4100020199953) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2050010099996 + 2050010099997.
It is an arithmetic number, because the mean of its divisors is an integer number (2050010099997).
Almost surely, 24100020199993 is an apocalyptic number.
It is an amenable number.
4100020199993 is a deficient number, since it is larger than the sum of its proper divisors (1).
4100020199993 is an equidigital number, since it uses as much as digits as its factorization.
4100020199993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 157464, while the sum is 47.
The spelling of 4100020199993 in words is "four trillion, one hundred billion, twenty million, one hundred ninety-nine thousand, nine hundred ninety-three".
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