Base | Representation |
---|---|
bin | 1011111011101101011… |
… | …01000101001000011111 |
3 | 1110012022112120220210102 |
4 | 11331312231011020133 |
5 | 23204201414001421 |
6 | 512205122331315 |
7 | 41423341404326 |
oct | 5756655051037 |
9 | 1405275526712 |
10 | 410013422111 |
11 | 148981984667 |
12 | 675687b9b3b |
13 | 2c883047b97 |
14 | 15bb801b0bd |
15 | a9eaa5860b |
hex | 5f76b4521f |
410013422111 has 2 divisors, whose sum is σ = 410013422112. Its totient is φ = 410013422110.
The previous prime is 410013422107. The next prime is 410013422263. The reversal of 410013422111 is 111224310014.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 410013422111 - 22 = 410013422107 is a prime.
It is a super-2 number, since 2×4100134221112 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (410013424111) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 205006711055 + 205006711056.
It is an arithmetic number, because the mean of its divisors is an integer number (205006711056).
Almost surely, 2410013422111 is an apocalyptic number.
410013422111 is a deficient number, since it is larger than the sum of its proper divisors (1).
410013422111 is an equidigital number, since it uses as much as digits as its factorization.
410013422111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 192, while the sum is 20.
Adding to 410013422111 its reverse (111224310014), we get a palindrome (521237732125).
The spelling of 410013422111 in words is "four hundred ten billion, thirteen million, four hundred twenty-two thousand, one hundred eleven".
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