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41001551 is a prime number
BaseRepresentation
bin1001110001101…
…0001001001111
32212011002112222
42130122021033
540444022201
64022445555
71005336023
oct234321117
985132488
1041001551
1121165088
12118938bb
138657696
145634383
1538ed91b
hex271a24f

41001551 has 2 divisors, whose sum is σ = 41001552. Its totient is φ = 41001550.

The previous prime is 41001547. The next prime is 41001557. The reversal of 41001551 is 15510014.

41001551 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 41001551 - 22 = 41001547 is a prime.

It is a super-2 number, since 2×410015512 = 3362254368811202, which contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (41001557) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20500775 + 20500776.

It is an arithmetic number, because the mean of its divisors is an integer number (20500776).

Almost surely, 241001551 is an apocalyptic number.

41001551 is a deficient number, since it is larger than the sum of its proper divisors (1).

41001551 is an equidigital number, since it uses as much as digits as its factorization.

41001551 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 100, while the sum is 17.

The square root of 41001551 is about 6403.2453490398. The cubic root of 41001551 is about 344.8260721013.

Adding to 41001551 its reverse (15510014), we get a palindrome (56511565).

The spelling of 41001551 in words is "forty-one million, one thousand, five hundred fifty-one".