Base | Representation |
---|---|
bin | 111011101010101100111… |
… | …100011111101101001011 |
3 | 112111222120222110220021011 |
4 | 323222230330133231023 |
5 | 1014134403341340133 |
6 | 12415352454224351 |
7 | 602144156555425 |
oct | 73525474375513 |
9 | 15458528426234 |
10 | 4100300340043 |
11 | 1340a22713686 |
12 | 5627ba3550b7 |
13 | 23986c8c497b |
14 | 102654221815 |
15 | 719d176e6cd |
hex | 3baacf1fb4b |
4100300340043 has 2 divisors, whose sum is σ = 4100300340044. Its totient is φ = 4100300340042.
The previous prime is 4100300340041. The next prime is 4100300340061. The reversal of 4100300340043 is 3400430030014.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4100300340043 - 21 = 4100300340041 is a prime.
Together with 4100300340041, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 4100300339996 and 4100300340023.
It is not a weakly prime, because it can be changed into another prime (4100300340041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2050150170021 + 2050150170022.
It is an arithmetic number, because the mean of its divisors is an integer number (2050150170022).
Almost surely, 24100300340043 is an apocalyptic number.
4100300340043 is a deficient number, since it is larger than the sum of its proper divisors (1).
4100300340043 is an equidigital number, since it uses as much as digits as its factorization.
4100300340043 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1728, while the sum is 22.
Adding to 4100300340043 its reverse (3400430030014), we get a palindrome (7500730370057).
The spelling of 4100300340043 in words is "four trillion, one hundred billion, three hundred million, three hundred forty thousand, forty-three".
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