Base | Representation |
---|---|
bin | 111011101010101101110… |
… | …000101110000011011101 |
3 | 112111222121221020102202202 |
4 | 323222231300232003131 |
5 | 1014134420342432201 |
6 | 12415354103501245 |
7 | 602144414124626 |
oct | 73525560560335 |
9 | 15458557212682 |
10 | 4100314030301 |
11 | 1340a2a414345 |
12 | 562802a57825 |
13 | 2398726a9108 |
14 | 102655d86a4d |
15 | 719d2a75c6b |
hex | 3baadc2e0dd |
4100314030301 has 2 divisors, whose sum is σ = 4100314030302. Its totient is φ = 4100314030300.
The previous prime is 4100314030291. The next prime is 4100314030313. The reversal of 4100314030301 is 1030304130014.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3601546155076 + 498767875225 = 1897774^2 + 706235^2 .
It is a cyclic number.
It is not a de Polignac number, because 4100314030301 - 210 = 4100314029277 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4100314030321) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2050157015150 + 2050157015151.
It is an arithmetic number, because the mean of its divisors is an integer number (2050157015151).
Almost surely, 24100314030301 is an apocalyptic number.
It is an amenable number.
4100314030301 is a deficient number, since it is larger than the sum of its proper divisors (1).
4100314030301 is an equidigital number, since it uses as much as digits as its factorization.
4100314030301 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 4100314030301 its reverse (1030304130014), we get a palindrome (5130618160315).
The spelling of 4100314030301 in words is "four trillion, one hundred billion, three hundred fourteen million, thirty thousand, three hundred one".
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