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4100343701413 is a prime number
BaseRepresentation
bin111011101010101111100…
…001111001111110100101
3112111222201000001212212211
4323222233201321332211
51014140000441421123
612415401043443421
7602145224253421
oct73525741717645
915458630055784
104100343701413
111340a4513a723
12562810986571
1323987889749b
14102659cabb81
15719d548740d
hex3baaf879fa5

4100343701413 has 2 divisors, whose sum is σ = 4100343701414. Its totient is φ = 4100343701412.

The previous prime is 4100343701381. The next prime is 4100343701437. The reversal of 4100343701413 is 3141073430014.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3836576203524 + 263767497889 = 1958718^2 + 513583^2 .

It is a cyclic number.

It is not a de Polignac number, because 4100343701413 - 25 = 4100343701381 is a prime.

It is a super-2 number, since 2×41003437014132 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4100343701513) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2050171850706 + 2050171850707.

It is an arithmetic number, because the mean of its divisors is an integer number (2050171850707).

Almost surely, 24100343701413 is an apocalyptic number.

It is an amenable number.

4100343701413 is a deficient number, since it is larger than the sum of its proper divisors (1).

4100343701413 is an equidigital number, since it uses as much as digits as its factorization.

4100343701413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12096, while the sum is 31.

The spelling of 4100343701413 in words is "four trillion, one hundred billion, three hundred forty-three million, seven hundred one thousand, four hundred thirteen".