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41004044104337 is a prime number
BaseRepresentation
bin10010101001010111111110…
…11110111011001010010001
312101011221121100001020000122
421110223333132323022101
520333302240242314322
6223112555310000025
711431305303110306
oct1124537736731221
9171157540036018
1041004044104337
1112079798a18456
124722a374a6015
1319b5884657742
14a1a86ba770ad
154b192151b442
hex254aff7bb291

41004044104337 has 2 divisors, whose sum is σ = 41004044104338. Its totient is φ = 41004044104336.

The previous prime is 41004044104259. The next prime is 41004044104339. The reversal of 41004044104337 is 73340144040014.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 40707960117841 + 296083986496 = 6380279^2 + 544136^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-41004044104337 is a prime.

Together with 41004044104339, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 41004044104297 and 41004044104306.

It is not a weakly prime, because it can be changed into another prime (41004044104339) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20502022052168 + 20502022052169.

It is an arithmetic number, because the mean of its divisors is an integer number (20502022052169).

Almost surely, 241004044104337 is an apocalyptic number.

It is an amenable number.

41004044104337 is a deficient number, since it is larger than the sum of its proper divisors (1).

41004044104337 is an equidigital number, since it uses as much as digits as its factorization.

41004044104337 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 64512, while the sum is 35.

The spelling of 41004044104337 in words is "forty-one trillion, four billion, forty-four million, one hundred four thousand, three hundred thirty-seven".