41004153331 has 2 divisors, whose sum is σ = 41004153332. Its totient is φ = 41004153330.

The previous prime is 41004153319. The next prime is 41004153361. The reversal of 41004153331 is 13335140014.

41004153331 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 41004153331 - 2²⁵ = 40970598899 is a prime.

It is a super-2 number, since 2×41004153331² (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 41004153296 and 41004153305.

It is not a weakly prime, because it can be changed into another prime (41004153301) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20502076665 + 20502076666.

It is an arithmetic number, because the mean of its divisors is an integer number (20502076666).

Almost surely, 2^41004153331 is an apocalyptic number.

41004153331 is a deficient number, since it is larger than the sum of its proper divisors (1).

41004153331 is an equidigital number, since it uses as much as digits as its factorization.

41004153331 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2160, while the sum is 25.

Adding to 41004153331 its reverse (13335140014), we get a palindrome (54339293345).

The spelling of 41004153331 in words is "forty-one billion, four million, one hundred fifty-three thousand, three hundred thirty-one".