Base | Representation |
---|---|
bin | 111011101010111011011… |
… | …011111010010010100001 |
3 | 112112000012220221111020022 |
4 | 323222323123322102201 |
5 | 1014140403111101132 |
6 | 12415432541123225 |
7 | 602153201200502 |
oct | 73527333722241 |
9 | 15460186844208 |
10 | 4100543456417 |
11 | 1341037975601 |
12 | 562867859515 |
13 | 2398ab097105 |
14 | 102678628ba9 |
15 | 719e7c93e12 |
hex | 3babb6fa4a1 |
4100543456417 has 2 divisors, whose sum is σ = 4100543456418. Its totient is φ = 4100543456416.
The previous prime is 4100543456413. The next prime is 4100543456453. The reversal of 4100543456417 is 7146543450014.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3402877506721 + 697665949696 = 1844689^2 + 835264^2 .
It is a cyclic number.
It is not a de Polignac number, because 4100543456417 - 22 = 4100543456413 is a prime.
It is not a weakly prime, because it can be changed into another prime (4100543456413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2050271728208 + 2050271728209.
It is an arithmetic number, because the mean of its divisors is an integer number (2050271728209).
Almost surely, 24100543456417 is an apocalyptic number.
It is an amenable number.
4100543456417 is a deficient number, since it is larger than the sum of its proper divisors (1).
4100543456417 is an equidigital number, since it uses as much as digits as its factorization.
4100543456417 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 806400, while the sum is 44.
The spelling of 4100543456417 in words is "four trillion, one hundred billion, five hundred forty-three million, four hundred fifty-six thousand, four hundred seventeen".
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