Base | Representation |
---|---|
bin | 111011101010111011011… |
… | …011111010010010011101 |
3 | 112112000012220221111020011 |
4 | 323222323123322102131 |
5 | 1014140403111101123 |
6 | 12415432541123221 |
7 | 602153201200465 |
oct | 73527333722235 |
9 | 15460186844204 |
10 | 4100543456413 |
11 | 13410379755a8 |
12 | 562867859511 |
13 | 2398ab097101 |
14 | 102678628ba5 |
15 | 719e7c93e0d |
hex | 3babb6fa49d |
4100543456413 has 2 divisors, whose sum is σ = 4100543456414. Its totient is φ = 4100543456412.
The previous prime is 4100543456371. The next prime is 4100543456417. The reversal of 4100543456413 is 3146543450014.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3561606877284 + 538936579129 = 1887222^2 + 734123^2 .
It is a cyclic number.
It is not a de Polignac number, because 4100543456413 - 29 = 4100543455901 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4100543456417) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2050271728206 + 2050271728207.
It is an arithmetic number, because the mean of its divisors is an integer number (2050271728207).
Almost surely, 24100543456413 is an apocalyptic number.
It is an amenable number.
4100543456413 is a deficient number, since it is larger than the sum of its proper divisors (1).
4100543456413 is an equidigital number, since it uses as much as digits as its factorization.
4100543456413 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 345600, while the sum is 40.
The spelling of 4100543456413 in words is "four trillion, one hundred billion, five hundred forty-three million, four hundred fifty-six thousand, four hundred thirteen".
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