Search a number
-
+
410100000053 is a prime number
BaseRepresentation
bin1011111011110111101…
…11010110010100110101
31110012112120111112101212
411331323313112110311
523204341100000203
6512221454131205
741425442325212
oct5757367262465
91405476445355
10410100000053
11148a16838987
12675917b0b05
132c897c6c333
1415bc5716b09
15aa0345b1d8
hex5f7bdd6535

410100000053 has 2 divisors, whose sum is σ = 410100000054. Its totient is φ = 410100000052.

The previous prime is 410100000007. The next prime is 410100000109. The reversal of 410100000053 is 350000001014.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 361251485764 + 48848514289 = 601042^2 + 221017^2 .

It is a cyclic number.

It is not a de Polignac number, because 410100000053 - 212 = 410099995957 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 410099999983 and 410100000037.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (410100000853) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 205050000026 + 205050000027.

It is an arithmetic number, because the mean of its divisors is an integer number (205050000027).

Almost surely, 2410100000053 is an apocalyptic number.

It is an amenable number.

410100000053 is a deficient number, since it is larger than the sum of its proper divisors (1).

410100000053 is an equidigital number, since it uses as much as digits as its factorization.

410100000053 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 60, while the sum is 14.

Adding to 410100000053 its reverse (350000001014), we get a palindrome (760100001067).

The spelling of 410100000053 in words is "four hundred ten billion, one hundred million, fifty-three", and thus it is an aban number.