Base | Representation |
---|---|
bin | 111011101100011010100… |
… | …111100000000110000011 |
3 | 112112011100012202002111002 |
4 | 323230122213200012003 |
5 | 1014202140411032441 |
6 | 12420255223442215 |
7 | 602240601330626 |
oct | 73543247400603 |
9 | 15464305662432 |
10 | 4102140330371 |
11 | 1341787301646 |
12 | 5630325b636b |
13 | 239aa3b77045 |
14 | 10278a747dbd |
15 | 71a8d076b9b |
hex | 3bb1a9e0183 |
4102140330371 has 2 divisors, whose sum is σ = 4102140330372. Its totient is φ = 4102140330370.
The previous prime is 4102140330289. The next prime is 4102140330373. The reversal of 4102140330371 is 1730330412014.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4102140330371 - 218 = 4102140068227 is a prime.
Together with 4102140330373, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (4102140330373) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2051070165185 + 2051070165186.
It is an arithmetic number, because the mean of its divisors is an integer number (2051070165186).
Almost surely, 24102140330371 is an apocalyptic number.
4102140330371 is a deficient number, since it is larger than the sum of its proper divisors (1).
4102140330371 is an equidigital number, since it uses as much as digits as its factorization.
4102140330371 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6048, while the sum is 29.
Adding to 4102140330371 its reverse (1730330412014), we get a palindrome (5832470742385).
The spelling of 4102140330371 in words is "four trillion, one hundred two billion, one hundred forty million, three hundred thirty thousand, three hundred seventy-one".
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