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410413131313 is a prime number
BaseRepresentation
bin1011111100011101000…
…01110110011000110001
31110020100101201020201221
411332032201312120301
523211011230200223
6512312521425041
741436264025303
oct5761641663061
91406311636657
10410413131313
11149067571049
126765a63b181
132c917ab6cc3
1415c15147973
15aa20bb0b5d
hex5f8e876631

410413131313 has 2 divisors, whose sum is σ = 410413131314. Its totient is φ = 410413131312.

The previous prime is 410413131257. The next prime is 410413131379. The reversal of 410413131313 is 313131314014.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 246912591409 + 163500539904 = 496903^2 + 404352^2 .

It is a cyclic number.

It is not a de Polignac number, because 410413131313 - 217 = 410413000241 is a prime.

It is a super-2 number, since 2×4104131313132 (a number of 24 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (410413131613) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 205206565656 + 205206565657.

It is an arithmetic number, because the mean of its divisors is an integer number (205206565657).

Almost surely, 2410413131313 is an apocalyptic number.

It is an amenable number.

410413131313 is a deficient number, since it is larger than the sum of its proper divisors (1).

410413131313 is an equidigital number, since it uses as much as digits as its factorization.

410413131313 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 410413131313 its reverse (313131314014), we get a palindrome (723544445327).

The spelling of 410413131313 in words is "four hundred ten billion, four hundred thirteen million, one hundred thirty-one thousand, three hundred thirteen".