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4104214212433 is a prime number
BaseRepresentation
bin111011101110010110001…
…110101110111101010001
3112112100200202010012211211
4323232112032232331101
51014220412314244213
612421241110140121
7602343153125206
oct73562616567521
915470622105754
104104214212433
111342650a20965
12563511051641
1323a04471bbaa
14102905d55cad
1571b6018053d
hex3bb963aef51

4104214212433 has 2 divisors, whose sum is σ = 4104214212434. Its totient is φ = 4104214212432.

The previous prime is 4104214212419. The next prime is 4104214212437. The reversal of 4104214212433 is 3342124124014.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3077329909824 + 1026884302609 = 1754232^2 + 1013353^2 .

It is a cyclic number.

It is not a de Polignac number, because 4104214212433 - 229 = 4103677341521 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 4104214212395 and 4104214212404.

It is not a weakly prime, because it can be changed into another prime (4104214212437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2052107106216 + 2052107106217.

It is an arithmetic number, because the mean of its divisors is an integer number (2052107106217).

Almost surely, 24104214212433 is an apocalyptic number.

It is an amenable number.

4104214212433 is a deficient number, since it is larger than the sum of its proper divisors (1).

4104214212433 is an equidigital number, since it uses as much as digits as its factorization.

4104214212433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18432, while the sum is 31.

Adding to 4104214212433 its reverse (3342124124014), we get a palindrome (7446338336447).

The spelling of 4104214212433 in words is "four trillion, one hundred four billion, two hundred fourteen million, two hundred twelve thousand, four hundred thirty-three".