Base | Representation |
---|---|
bin | 111011101110100010000… |
… | …101111101111011000111 |
3 | 112112101012121121220202101 |
4 | 323232202011331323013 |
5 | 1014221314242203111 |
6 | 12421312540052531 |
7 | 602351120625415 |
oct | 73564205757307 |
9 | 15471177556671 |
10 | 4104413241031 |
11 | 1342743300004 |
12 | 563567834147 |
13 | 23a076a25cac |
14 | 1029245642b5 |
15 | 71b72896bc1 |
hex | 3bba217dec7 |
4104413241031 has 2 divisors, whose sum is σ = 4104413241032. Its totient is φ = 4104413241030.
The previous prime is 4104413240971. The next prime is 4104413241079. The reversal of 4104413241031 is 1301423144014.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4104413241031 - 213 = 4104413232839 is a prime.
It is a super-2 number, since 2×41044132410312 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4104413241091) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2052206620515 + 2052206620516.
It is an arithmetic number, because the mean of its divisors is an integer number (2052206620516).
Almost surely, 24104413241031 is an apocalyptic number.
4104413241031 is a deficient number, since it is larger than the sum of its proper divisors (1).
4104413241031 is an equidigital number, since it uses as much as digits as its factorization.
4104413241031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4608, while the sum is 28.
Adding to 4104413241031 its reverse (1301423144014), we get a palindrome (5405836385045).
The spelling of 4104413241031 in words is "four trillion, one hundred four billion, four hundred thirteen million, two hundred forty-one thousand, thirty-one".
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