Base | Representation |
---|---|
bin | 111011101111001100111… |
… | …001100100101101001111 |
3 | 112112110001122222210112101 |
4 | 323233030321210231033 |
5 | 1014224302120143203 |
6 | 12421512113015531 |
7 | 602404661161255 |
oct | 73571471445517 |
9 | 15473048883471 |
10 | 4105131412303 |
11 | 1342a81730789 |
12 | 5637282545a7 |
13 | 23a15c7582cc |
14 | 102991aac5d5 |
15 | 71bb595841d |
hex | 3bbcce64b4f |
4105131412303 has 2 divisors, whose sum is σ = 4105131412304. Its totient is φ = 4105131412302.
The previous prime is 4105131412289. The next prime is 4105131412309. The reversal of 4105131412303 is 3032141315014.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4105131412303 - 221 = 4105129315151 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4105131412309) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2052565706151 + 2052565706152.
It is an arithmetic number, because the mean of its divisors is an integer number (2052565706152).
Almost surely, 24105131412303 is an apocalyptic number.
4105131412303 is a deficient number, since it is larger than the sum of its proper divisors (1).
4105131412303 is an equidigital number, since it uses as much as digits as its factorization.
4105131412303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4320, while the sum is 28.
Adding to 4105131412303 its reverse (3032141315014), we get a palindrome (7137272727317).
The spelling of 4105131412303 in words is "four trillion, one hundred five billion, one hundred thirty-one million, four hundred twelve thousand, three hundred three".
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