4105401311131 has 2 divisors, whose sum is σ = 4105401311132. Its totient is φ = 4105401311130.

The previous prime is 4105401311101. The next prime is 4105401311147. The reversal of 4105401311131 is 1311131045014.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-4105401311131 is a prime.

It is a super-2 number, since 2×4105401311131² (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 4105401311096 and 4105401311105.

It is not a weakly prime, because it can be changed into another prime (4105401311101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2052700655565 + 2052700655566.

It is an arithmetic number, because the mean of its divisors is an integer number (2052700655566).

Almost surely, 2^{4105401311131} is an apocalyptic number.

4105401311131 is a deficient number, since it is larger than the sum of its proper divisors (1).

4105401311131 is an equidigital number, since it uses as much as digits as its factorization.

4105401311131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 720, while the sum is 25.

Adding to 4105401311131 its reverse (1311131045014), we get a palindrome (5416532356145).

The spelling of 4105401311131 in words is "four trillion, one hundred five billion, four hundred one million, three hundred eleven thousand, one hundred thirty-one".