41100113243129 has 2 divisors, whose sum is σ = 41100113243130. Its totient is φ = 41100113243128.

The previous prime is 41100113243071. The next prime is 41100113243219. The reversal of 41100113243129 is 92134231100114.

Together with next prime (41100113243219) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 24114463779904 + 16985649463225 = 4910648^2 + 4121365^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-41100113243129 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 41100113243095 and 41100113243104.

It is not a weakly prime, because it can be changed into another prime (41100113243029) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20550056621564 + 20550056621565.

It is an arithmetic number, because the mean of its divisors is an integer number (20550056621565).

Almost surely, 2^{41100113243129} is an apocalyptic number.

It is an amenable number.

41100113243129 is a deficient number, since it is larger than the sum of its proper divisors (1).

41100113243129 is an equidigital number, since it uses as much as digits as its factorization.

41100113243129 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5184, while the sum is 32.

The spelling of 41100113243129 in words is "forty-one trillion, one hundred billion, one hundred thirteen million, two hundred forty-three thousand, one hundred twenty-nine".