Base | Representation |
---|---|
bin | 11000011111110… |
… | …110101000010101 |
3 | 1001122101010200122 |
4 | 120133312220111 |
5 | 1320204102123 |
6 | 104441121325 |
7 | 13120320452 |
oct | 3037665025 |
9 | 1048333618 |
10 | 411003413 |
11 | 1a1000a47 |
12 | b5789245 |
13 | 671c4ab2 |
14 | 3c82a829 |
15 | 26138bc8 |
hex | 187f6a15 |
411003413 has 2 divisors, whose sum is σ = 411003414. Its totient is φ = 411003412.
The previous prime is 411003389. The next prime is 411003433. The reversal of 411003413 is 314300114.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 362255089 + 48748324 = 19033^2 + 6982^2 .
It is a cyclic number.
It is not a de Polignac number, because 411003413 - 26 = 411003349 is a prime.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 411003391 and 411003400.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (411003433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 205501706 + 205501707.
It is an arithmetic number, because the mean of its divisors is an integer number (205501707).
Almost surely, 2411003413 is an apocalyptic number.
It is an amenable number.
411003413 is a deficient number, since it is larger than the sum of its proper divisors (1).
411003413 is an equidigital number, since it uses as much as digits as its factorization.
411003413 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 17.
The square root of 411003413 is about 20273.2191079759. The cubic root of 411003413 is about 743.5014321959.
Adding to 411003413 its reverse (314300114), we get a palindrome (725303527).
The spelling of 411003413 in words is "four hundred eleven million, three thousand, four hundred thirteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.064 sec. • engine limits •