41101321411 has 4 divisors (see below), whose sum is σ = 41525046472. Its totient is φ = 40677596352.

The previous prime is 41101321409. The next prime is 41101321423. The reversal of 41101321411 is 11412310114.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 11412310114 = 2 ⋅5706155057.

It is a cyclic number.

It is not a de Polignac number, because 41101321411 - 2¹ = 41101321409 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (41101322411) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 211862385 + ... + 211862578.

It is an arithmetic number, because the mean of its divisors is an integer number (10381261618).

Almost surely, 2^41101321411 is an apocalyptic number.

41101321411 is a deficient number, since it is larger than the sum of its proper divisors (423725061).

41101321411 is an equidigital number, since it uses as much as digits as its factorization.

41101321411 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 423725060.

The product of its (nonzero) digits is 96, while the sum is 19.

Adding to 41101321411 its reverse (11412310114), we get a palindrome (52513631525).

The spelling of 41101321411 in words is "forty-one billion, one hundred one million, three hundred twenty-one thousand, four hundred eleven".