4110401320021 has 2 divisors, whose sum is σ = 4110401320022. Its totient is φ = 4110401320020.

The previous prime is 4110401320009. The next prime is 4110401320043. The reversal of 4110401320021 is 1200231040114.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3384812525796 + 725588794225 = 1839786^2 + 851815^2 .

It is a cyclic number.

It is not a de Polignac number, because 4110401320021 - 2⁵ = 4110401319989 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4110401320061) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2055200660010 + 2055200660011.

It is an arithmetic number, because the mean of its divisors is an integer number (2055200660011).

Almost surely, 2^{4110401320021} is an apocalyptic number.

It is an amenable number.

4110401320021 is a deficient number, since it is larger than the sum of its proper divisors (1).

4110401320021 is an equidigital number, since it uses as much as digits as its factorization.

4110401320021 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 192, while the sum is 19.

Adding to 4110401320021 its reverse (1200231040114), we get a palindrome (5310632360135).

The spelling of 4110401320021 in words is "four trillion, one hundred ten billion, four hundred one million, three hundred twenty thousand, twenty-one".