Base | Representation |
---|---|
bin | 101110101110101101100100… |
… | …0100000111100111110001100 |
3 | 1222220101001220221002121012022 |
4 | 1131131123020200330332030 |
5 | 412333441041001241330 |
6 | 4014113152415025312 |
7 | 152402453262420431 |
oct | 13535331040747614 |
9 | 1886331827077168 |
10 | 411040324243340 |
11 | 109a7424a266450 |
12 | 3a126450b0b238 |
13 | 14847c22c5cb0c |
14 | 737065a471b88 |
15 | 327c17e9bbae5 |
hex | 175d6c883cf8c |
411040324243340 has 96 divisors (see below), whose sum is σ = 943009930469376. Its totient is φ = 149254331754240.
The previous prime is 411040324243331. The next prime is 411040324243343. The reversal of 411040324243340 is 43342423040114.
It is a self number, because there is not a number n which added to its sum of digits gives 411040324243340.
It is not an unprimeable number, because it can be changed into a prime (411040324243343) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2383820369 + ... + 2383992791.
It is an arithmetic number, because the mean of its divisors is an integer number (9823020109056).
Almost surely, 2411040324243340 is an apocalyptic number.
It is an amenable number.
411040324243340 is an abundant number, since it is smaller than the sum of its proper divisors (531969606226036).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
411040324243340 is a wasteful number, since it uses less digits than its factorization.
411040324243340 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 187959 (or 187957 counting only the distinct ones).
The product of its (nonzero) digits is 110592, while the sum is 35.
Adding to 411040324243340 its reverse (43342423040114), we get a palindrome (454382747283454).
The spelling of 411040324243340 in words is "four hundred eleven trillion, forty billion, three hundred twenty-four million, two hundred forty-three thousand, three hundred forty".
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