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411043150121 is a prime number
BaseRepresentation
bin1011111101101000001…
…01001011100100101001
31110021222022012112001212
411332310011023210221
523213304021300441
6512455225122505
741461014061652
oct5766405134451
91407868175055
10411043150121
1114936016254a
12677b5629435
132c9b84932b6
1415c74aa6529
15aa5b15ceeb
hex5fb414b929

411043150121 has 2 divisors, whose sum is σ = 411043150122. Its totient is φ = 411043150120.

The previous prime is 411043150087. The next prime is 411043150123. The reversal of 411043150121 is 121051340114.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 389120202025 + 21922948096 = 623795^2 + 148064^2 .

It is a cyclic number.

It is not a de Polignac number, because 411043150121 - 218 = 411042887977 is a prime.

It is a super-2 number, since 2×4110431501212 (a number of 24 digits) contains 22 as substring.

Together with 411043150123, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (411043150123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 205521575060 + 205521575061.

It is an arithmetic number, because the mean of its divisors is an integer number (205521575061).

Almost surely, 2411043150121 is an apocalyptic number.

It is an amenable number.

411043150121 is a deficient number, since it is larger than the sum of its proper divisors (1).

411043150121 is an equidigital number, since it uses as much as digits as its factorization.

411043150121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 480, while the sum is 23.

Adding to 411043150121 its reverse (121051340114), we get a palindrome (532094490235).

The spelling of 411043150121 in words is "four hundred eleven billion, forty-three million, one hundred fifty thousand, one hundred twenty-one".