Base | Representation |
---|---|
bin | 1011111101101001010… |
… | …11101001100000011011 |
3 | 1110022000000011211211101 |
4 | 11332310223221200123 |
5 | 23213314111443303 |
6 | 512500225212231 |
7 | 41461165561423 |
oct | 5766453514033 |
9 | 1408000154741 |
10 | 411053234203 |
11 | 14936591a8a7 |
12 | 677b8a91077 |
13 | 2c9ba5b4201 |
14 | 15c7616d483 |
15 | aa5bea0d1d |
hex | 5fb4ae981b |
411053234203 has 2 divisors, whose sum is σ = 411053234204. Its totient is φ = 411053234202.
The previous prime is 411053234159. The next prime is 411053234257. The reversal of 411053234203 is 302432350114.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 411053234203 - 213 = 411053226011 is a prime.
It is a super-2 number, since 2×4110532342032 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (411053264203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 205526617101 + 205526617102.
It is an arithmetic number, because the mean of its divisors is an integer number (205526617102).
Almost surely, 2411053234203 is an apocalyptic number.
411053234203 is a deficient number, since it is larger than the sum of its proper divisors (1).
411053234203 is an equidigital number, since it uses as much as digits as its factorization.
411053234203 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8640, while the sum is 28.
Adding to 411053234203 its reverse (302432350114), we get a palindrome (713485584317).
The spelling of 411053234203 in words is "four hundred eleven billion, fifty-three million, two hundred thirty-four thousand, two hundred three".
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