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41107433 is a prime number
BaseRepresentation
bin1001110011001…
…1111111101001
32212100110210112
42130303333221
541010414213
64025024105
71006256513
oct234637751
985313715
1041107433
1121227694
1211925035
138693933
145660bb3
15391eea8
hex2733fe9

41107433 has 2 divisors, whose sum is σ = 41107434. Its totient is φ = 41107432.

The previous prime is 41107427. The next prime is 41107439. The reversal of 41107433 is 33470114.

It is a balanced prime because it is at equal distance from previous prime (41107427) and next prime (41107439).

It can be written as a sum of positive squares in only one way, i.e., 22686169 + 18421264 = 4763^2 + 4292^2 .

It is a cyclic number.

It is not a de Polignac number, because 41107433 - 220 = 40058857 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 41107399 and 41107408.

It is not a weakly prime, because it can be changed into another prime (41107439) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20553716 + 20553717.

It is an arithmetic number, because the mean of its divisors is an integer number (20553717).

Almost surely, 241107433 is an apocalyptic number.

It is an amenable number.

41107433 is a deficient number, since it is larger than the sum of its proper divisors (1).

41107433 is an equidigital number, since it uses as much as digits as its factorization.

41107433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1008, while the sum is 23.

The square root of 41107433 is about 6411.5078569709. The cubic root of 41107433 is about 345.1226421078.

Adding to 41107433 its reverse (33470114), we get a palindrome (74577547).

The spelling of 41107433 in words is "forty-one million, one hundred seven thousand, four hundred thirty-three".