Base | Representation |
---|---|
bin | 10010101100011101100110… |
… | …11010101111000011000110 |
3 | 12101120002110111011212100021 |
4 | 21112032303122233003012 |
5 | 20342022032340321014 |
6 | 223233423310405354 |
7 | 11442052434263443 |
oct | 1126166332570306 |
9 | 171502414155307 |
10 | 41110142120134 |
11 | 1210a79354002a |
12 | 473b50750085a |
13 | 19c2892630549 |
14 | a21a5493c9ca |
15 | 4b4580ca0624 |
hex | 2563b36af0c6 |
41110142120134 has 16 divisors (see below), whose sum is σ = 63440355429360. Its totient is φ = 19967660352640.
The previous prime is 41110142120123. The next prime is 41110142120137. The reversal of 41110142120134 is 43102124101114.
It is a super-2 number, since 2×411101421201342 (a number of 28 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 41110142120099 and 41110142120108.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (41110142120137) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1075824664 + ... + 1075862875.
It is an arithmetic number, because the mean of its divisors is an integer number (3965022214335).
Almost surely, 241110142120134 is an apocalyptic number.
41110142120134 is a deficient number, since it is larger than the sum of its proper divisors (22330213309226).
41110142120134 is a wasteful number, since it uses less digits than its factorization.
41110142120134 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2151687815.
The product of its (nonzero) digits is 768, while the sum is 25.
Adding to 41110142120134 its reverse (43102124101114), we get a palindrome (84212266221248).
The spelling of 41110142120134 in words is "forty-one trillion, one hundred ten billion, one hundred forty-two million, one hundred twenty thousand, one hundred thirty-four".
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