41113141471 has 2 divisors, whose sum is σ = 41113141472. Its totient is φ = 41113141470.

The previous prime is 41113141417. The next prime is 41113141523. The reversal of 41113141471 is 17414131114.

Together with previous prime (41113141417) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 41113141471 - 2¹⁷ = 41113010399 is a prime.

It is a super-3 number, since 3×41113141471³ (a number of 33 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (41113141271) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20556570735 + 20556570736.

It is an arithmetic number, because the mean of its divisors is an integer number (20556570736).

Almost surely, 2^41113141471 is an apocalyptic number.

41113141471 is a deficient number, since it is larger than the sum of its proper divisors (1).

41113141471 is an equidigital number, since it uses as much as digits as its factorization.

41113141471 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1344, while the sum is 28.

Adding to 41113141471 its reverse (17414131114), we get a palindrome (58527272585).

The spelling of 41113141471 in words is "forty-one billion, one hundred thirteen million, one hundred forty-one thousand, four hundred seventy-one".