Base | Representation |
---|---|
bin | 10010101100100011011111… |
… | …01101011010100001011011 |
3 | 12101120101121122102100212201 |
4 | 21112101233231122201123 |
5 | 20342100020042232103 |
6 | 223235104555151031 |
7 | 11442223633405612 |
oct | 1126215755324133 |
9 | 171511548370781 |
10 | 41113301133403 |
11 | 121110647394a4 |
12 | 4740049445477 |
13 | 19c2c76c4b375 |
14 | a21c742d8879 |
15 | 4b46b82a451d |
hex | 25646fb5a85b |
41113301133403 has 2 divisors, whose sum is σ = 41113301133404. Its totient is φ = 41113301133402.
The previous prime is 41113301133397. The next prime is 41113301133419. The reversal of 41113301133403 is 30433110331114.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 41113301133403 - 25 = 41113301133371 is a prime.
It is not a weakly prime, because it can be changed into another prime (41113301193403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20556650566701 + 20556650566702.
It is an arithmetic number, because the mean of its divisors is an integer number (20556650566702).
Almost surely, 241113301133403 is an apocalyptic number.
41113301133403 is a deficient number, since it is larger than the sum of its proper divisors (1).
41113301133403 is an equidigital number, since it uses as much as digits as its factorization.
41113301133403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3888, while the sum is 28.
Adding to 41113301133403 its reverse (30433110331114), we get a palindrome (71546411464517).
The spelling of 41113301133403 in words is "forty-one trillion, one hundred thirteen billion, three hundred one million, one hundred thirty-three thousand, four hundred three".
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