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411143241103 = 758734748729
BaseRepresentation
bin1011111101110100000…
…10111111110110001111
31110022020021112200002021
411332322002333312033
523214010132203403
6512513202311011
741463340613260
oct5767202776617
91408207480067
10411143241103
11149401706371
1267823058467
132ca0313932a
1415c840bc967
15aa64d2e8bd
hex5fba0bfd8f

411143241103 has 4 divisors (see below), whose sum is σ = 469877989840. Its totient is φ = 352408492368.

The previous prime is 411143241083. The next prime is 411143241151. The reversal of 411143241103 is 301142341114.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 301142341114 = 2150571170557.

It is a cyclic number.

It is not a de Polignac number, because 411143241103 - 217 = 411143110031 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (411143241403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29367374358 + ... + 29367374371.

It is an arithmetic number, because the mean of its divisors is an integer number (117469497460).

Almost surely, 2411143241103 is an apocalyptic number.

411143241103 is a deficient number, since it is larger than the sum of its proper divisors (58734748737).

411143241103 is an equidigital number, since it uses as much as digits as its factorization.

411143241103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 58734748736.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 411143241103 its reverse (301142341114), we get a palindrome (712285582217).

The spelling of 411143241103 in words is "four hundred eleven billion, one hundred forty-three million, two hundred forty-one thousand, one hundred three".

Divisors: 1 7 58734748729 411143241103