Base | Representation |
---|---|
bin | 100110010010101011… |
… | …110000110000101001 |
3 | 10221010102100111010002 |
4 | 212102223300300221 |
5 | 1133201101313423 |
6 | 30515511032345 |
7 | 2653612160645 |
oct | 462253606051 |
9 | 127112314102 |
10 | 41115651113 |
11 | 16489793259 |
12 | 7b7566b6b5 |
13 | 3b53253054 |
14 | 1dc0821c25 |
15 | 1109910228 |
hex | 992af0c29 |
41115651113 has 2 divisors, whose sum is σ = 41115651114. Its totient is φ = 41115651112.
The previous prime is 41115651097. The next prime is 41115651131. The reversal of 41115651113 is 31115651114.
Together with next prime (41115651131) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 24588748864 + 16526902249 = 156808^2 + 128557^2 .
It is a cyclic number.
It is not a de Polignac number, because 41115651113 - 24 = 41115651097 is a prime.
It is not a weakly prime, because it can be changed into another prime (41115651193) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20557825556 + 20557825557.
It is an arithmetic number, because the mean of its divisors is an integer number (20557825557).
Almost surely, 241115651113 is an apocalyptic number.
It is an amenable number.
41115651113 is a deficient number, since it is larger than the sum of its proper divisors (1).
41115651113 is an equidigital number, since it uses as much as digits as its factorization.
41115651113 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1800, while the sum is 29.
Subtracting from 41115651113 its reverse (31115651114), we obtain a palindrome (9999999999).
The spelling of 41115651113 in words is "forty-one billion, one hundred fifteen million, six hundred fifty-one thousand, one hundred thirteen".
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