41115651131 has 2 divisors, whose sum is σ = 41115651132. Its totient is φ = 41115651130.

The previous prime is 41115651113. The next prime is 41115651139. The reversal of 41115651131 is 13115651114.

41115651131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

Together with previous prime (41115651113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 41115651131 - 2¹⁸ = 41115388987 is a prime.

It is a super-2 number, since 2×41115651131² (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 41115651094 and 41115651103.

It is not a weakly prime, because it can be changed into another prime (41115651139) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20557825565 + 20557825566.

It is an arithmetic number, because the mean of its divisors is an integer number (20557825566).

Almost surely, 2^41115651131 is an apocalyptic number.

41115651131 is a deficient number, since it is larger than the sum of its proper divisors (1).

41115651131 is an equidigital number, since it uses as much as digits as its factorization.

41115651131 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1800, while the sum is 29.

The spelling of 41115651131 in words is "forty-one billion, one hundred fifteen million, six hundred fifty-one thousand, one hundred thirty-one".