Base | Representation |
---|---|
bin | 10010101100110000011010… |
… | …10100101000011011110101 |
3 | 12101121001112020212211212201 |
4 | 21112120031110220123311 |
5 | 20342203223020413323 |
6 | 223242213323544501 |
7 | 11442560614263055 |
oct | 1126301524503365 |
9 | 171531466784781 |
10 | 41120240404213 |
11 | 12113aa5784353 |
12 | 474146538b131 |
13 | 19c38117b0479 |
14 | a22331b67565 |
15 | 4b49725c48ad |
hex | 25660d5286f5 |
41120240404213 has 2 divisors, whose sum is σ = 41120240404214. Its totient is φ = 41120240404212.
The previous prime is 41120240404163. The next prime is 41120240404283. The reversal of 41120240404213 is 31240404202114.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 32536266259249 + 8583974144964 = 5704057^2 + 2929842^2 .
It is a cyclic number.
It is not a de Polignac number, because 41120240404213 - 233 = 41111650469621 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (41120240404283) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20560120202106 + 20560120202107.
It is an arithmetic number, because the mean of its divisors is an integer number (20560120202107).
Almost surely, 241120240404213 is an apocalyptic number.
It is an amenable number.
41120240404213 is a deficient number, since it is larger than the sum of its proper divisors (1).
41120240404213 is an equidigital number, since it uses as much as digits as its factorization.
41120240404213 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6144, while the sum is 28.
Adding to 41120240404213 its reverse (31240404202114), we get a palindrome (72360644606327).
The spelling of 41120240404213 in words is "forty-one trillion, one hundred twenty billion, two hundred forty million, four hundred four thousand, two hundred thirteen".
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