Search a number
-
+
4112027773649 is a prime number
BaseRepresentation
bin111011110101100111111…
…101000110101011010001
3112120002212021201020210222
4323311213331012223101
51014332413102224044
612425012310002425
7603040611242105
oct73654775065321
915502767636728
104112027773649
1113459a0529074
12564b31946415
1323a9bb4454b3
1410304796b905
1571e6b0ee8ee
hex3bd67f46ad1

4112027773649 has 2 divisors, whose sum is σ = 4112027773650. Its totient is φ = 4112027773648.

The previous prime is 4112027773613. The next prime is 4112027773709. The reversal of 4112027773649 is 9463777202114.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2092744143424 + 2019283630225 = 1446632^2 + 1421015^2 .

It is a cyclic number.

It is not a de Polignac number, because 4112027773649 - 28 = 4112027773393 is a prime.

It is a super-2 number, since 2×41120277736492 (a number of 26 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 4112027773649.

It is not a weakly prime, because it can be changed into another prime (4112027773549) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2056013886824 + 2056013886825.

It is an arithmetic number, because the mean of its divisors is an integer number (2056013886825).

Almost surely, 24112027773649 is an apocalyptic number.

It is an amenable number.

4112027773649 is a deficient number, since it is larger than the sum of its proper divisors (1).

4112027773649 is an equidigital number, since it uses as much as digits as its factorization.

4112027773649 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3556224, while the sum is 53.

The spelling of 4112027773649 in words is "four trillion, one hundred twelve billion, twenty-seven million, seven hundred seventy-three thousand, six hundred forty-nine".