Base | Representation |
---|---|
bin | 111011110101101101000… |
… | …000010101000111011011 |
3 | 112120010002012011001210112 |
4 | 323311231000111013123 |
5 | 1014333101300132212 |
6 | 12425024534034535 |
7 | 603042660403142 |
oct | 73655500250733 |
9 | 15503065131715 |
10 | 4112112505307 |
11 | 1345a34341234 |
12 | 564b561a8a4b |
13 | 23aa02b71481 |
14 | 103054d06759 |
15 | 71e7378a422 |
hex | 3bd6d0151db |
4112112505307 has 2 divisors, whose sum is σ = 4112112505308. Its totient is φ = 4112112505306.
The previous prime is 4112112505273. The next prime is 4112112505343. The reversal of 4112112505307 is 7035052112114.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4112112505307 - 218 = 4112112243163 is a prime.
It is not a weakly prime, because it can be changed into another prime (4112112505357) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2056056252653 + 2056056252654.
It is an arithmetic number, because the mean of its divisors is an integer number (2056056252654).
Almost surely, 24112112505307 is an apocalyptic number.
4112112505307 is a deficient number, since it is larger than the sum of its proper divisors (1).
4112112505307 is an equidigital number, since it uses as much as digits as its factorization.
4112112505307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8400, while the sum is 32.
The spelling of 4112112505307 in words is "four trillion, one hundred twelve billion, one hundred twelve million, five hundred five thousand, three hundred seven".
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