41121131 has 2 divisors, whose sum is σ = 41121132. Its totient is φ = 41121130.

The previous prime is 41121127. The next prime is 41121167. The reversal of 41121131 is 13112114.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 41121131 - 2² = 41121127 is a prime.

It is a super-3 number, since 3×41121131³ (a number of 24 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Sophie Germain prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (41121191) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20560565 + 20560566.

It is an arithmetic number, because the mean of its divisors is an integer number (20560566).

Almost surely, 2^41121131 is an apocalyptic number.

41121131 is a deficient number, since it is larger than the sum of its proper divisors (1).

41121131 is an equidigital number, since it uses as much as digits as its factorization.

41121131 is an evil number, because the sum of its binary digits is even.

The product of its digits is 24, while the sum is 14.

The square root of 41121131 is about 6412.5760034482. The cubic root of 41121131 is about 345.1609722799.

Adding to 41121131 its reverse (13112114), we get a palindrome (54233245).

It can be divided in two parts, 4112113 and 1, that added together give a palindrome (4112114).

The spelling of 41121131 in words is "forty-one million, one hundred twenty-one thousand, one hundred thirty-one".