411211310400 has 504 divisors, whose sum is σ = 1637525039904. Its totient is φ = 96991948800.

The previous prime is 411211310309. The next prime is 411211310423. The reversal of 411211310400 is 4013112114.

411211310400 is a `hidden beast` number, since 41 + 1 + 211 + 3 + 10 + 400 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 5825719 + ... + 5895881.

Almost surely, 2^411211310400 is an apocalyptic number.

411211310400 is a gapful number since it is divisible by the number (40) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 411211310400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (818762519952).

411211310400 is an abundant number, since it is smaller than the sum of its proper divisors (1226313729504).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

411211310400 is a wasteful number, since it uses less digits than its factorization.

411211310400 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 70239 (or 70221 counting only the distinct ones).

The product of its (nonzero) digits is 96, while the sum is 18.

Adding to 411211310400 its reverse (4013112114), we get a palindrome (415224422514).

The spelling of 411211310400 in words is "four hundred eleven billion, two hundred eleven million, three hundred ten thousand, four hundred".